(5x-1)(x^2-2x+1)=0

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Solution for (5x-1)(x^2-2x+1)=0 equation: 


Simplifying
(5x + -1)(x2 + -2x + 1) = 0

Reorder the terms:
(-1 + 5x)(x2 + -2x + 1) = 0

Reorder the terms:
(-1 + 5x)(1 + -2x + x2) = 0

Multiply (-1 + 5x) * (1 + -2x + x2)
(-1(1 + -2x + x2) + 5x * (1 + -2x + x2)) = 0
((1 * -1 + -2x * -1 + x2 * -1) + 5x * (1 + -2x + x2)) = 0
((-1 + 2x + -1x2) + 5x * (1 + -2x + x2)) = 0
(-1 + 2x + -1x2 + (1 * 5x + -2x * 5x + x2 * 5x)) = 0
(-1 + 2x + -1x2 + (5x + -10x2 + 5x3)) = 0

Reorder the terms:
(-1 + 2x + 5x + -1x2 + -10x2 + 5x3) = 0

Combine like terms: 2x + 5x = 7x
(-1 + 7x + -1x2 + -10x2 + 5x3) = 0

Combine like terms: -1x2 + -10x2 = -11x2
(-1 + 7x + -11x2 + 5x3) = 0

Solving
-1 + 7x + -11x2 + 5x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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